y^2+y=198

Solution for y^2+y=198 equation:

y^2+y=198

We move all terms to the left:

y^2+y-(198)=0

a = 1; b = 1; c = -198;
Δ = b2-4ac
Δ = 12-4·1·(-198)
Δ = 793
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{793}}{2*1}=\frac{-1-\sqrt{793}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{793}}{2*1}=\frac{-1+\sqrt{793}}{2}
$